-x^2+3x-10x=-2

Solution for -x^2+3x-10x=-2 equation:

-x^2+3x-10x=-2

We move all terms to the left:

-x^2+3x-10x-(-2)=0

We add all the numbers together, and all the variables

-1x^2-7x+2=0

a = -1; b = -7; c = +2;
Δ = b2-4ac
Δ = -72-4·(-1)·2
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{57}}{2*-1}=\frac{7-\sqrt{57}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{57}}{2*-1}=\frac{7+\sqrt{57}}{-2}
$